Write a function, `rec_intersection(rect1, rect2)` and returns the intersection of the two.

Rectangles are represented as a pair of coordinate-pairs: the bottom-left and top-right coordinates (given in `[x, y]` notation).

Hint: You can calculate the left-most x coordinate of the intersection by taking the maximum of the left-most x coordinate of each rectangle. Likewise, you can calculate the top-most y coordinate of the intersection by taking the minimum of the top most y coordinate of each rectangle.

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This is probably the hardest problem I’ve encountered do date. It’s a bit more logic than math and I definitely overcomplicated it by trying to make sense of it with math, which is not my strength..

Some helpful things to remember:

- Plot out the coordinates and draw the rectangles on a piece of paper first.
- Try not to confuse the (x,y) coordinates with arrays. (This part tripped me up the most).
- The trick is to use max and min to get the left and right coordinates of the intersection, respectively. (This is a bit counterintuitive).
- To access a value of a
*multidimensional array*, use **a[i][j]**, where **i** is the index of **a**, and **j** is the index of **a[i]** array.

Anyways, here’s the solution with my annotated comments:

**Test Cases: **

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